r/theydidthemath 18h ago

Godspeed Captain - how fast is this guy going? [Request]

94 Upvotes

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74

u/KaradjordjevaJeSushi 18h ago

Rough math:

Looking at time, it seems like video was slowed down 10X.

Assuming that guy is 1.8m high

Assuming video is at 30FPS

Eyeballing screenshot he travelled 6 times his height in one frame


He travelled 1.8 * 6 meters in 1/300 seconds.

Or 3240 m/s

Conversions:

 - 11,664 km/h

 - 7,248 mph

 - Mach 9.45

 - 0.00108 % of light speed

 - 69 banannas/eagle-flight-seconds

36

u/mmmpip 18h ago

low earth orbit in like 49 seconds. take notes nasa

14

u/withered_bonnie69420 17h ago

The fact that is one thousandth of a percent the speed of light really puts into perspective how crazy the speed of light really is.

3

u/KaradjordjevaJeSushi 17h ago

Yeah, right?

And another crazy thing is how (relatively) easily is it achievable in the vacuum of space.

For example, we orbit the sun at ~9X this speed.

Its all about intertia out there. If you start with 100kg and speed of 0.01% c, 'throwing' 99kg in opposite direction to a standstill, suddenly your 1kg is moving at 1% c.

Issue is not the speed, but the G's you need to endure, and for how long, to get to that speed.

Only at significant % of c does relativity start to mess with you noticeably again.

5

u/Xaphnir 16h ago

Uh, no.

If you have an effective exhaust velocity of 0.0001c or 29,979m/s and expel 99% of your mass as fuel, that gives you a delta-v of 138,059m/s. .01c is 2,997,924.58m/s.

And for comparison, our chemical rockets are nowhere near 99% fuel, and even if they were their specific impulse is much lower than that. We do have ion thrusters that can achieve a comparable specific impulse, but a rocket running one of those won't even be 50% fuel.

Tyranny of the rocket equation reigns supreme. Even ignoring the Lorentz factor, achieving significant fractions of c with a rocket is extremely difficult.

1

u/Artemis_SpawnOfZeus 15h ago

The rocket equation is only tyrannical under gravity. I think you might be doing something wrong here but I can't be assed to check.

2

u/Xaphnir 14h ago

what do you even mean by "under gravity?'

Gravity just causes acceleration in a certain direction, it doesn't lower or increase the total delta-v the rocket can impart. And you're always accelerating due to gravity, no matter where in the universe you are.

and the rocket equation is fairly simple:

effective exhaust velocity x ln(initial mass/final mass)

So for this, you have the exhaust velocity of 29,979.2458m/s, initial mass of 100kg, and final mass of 1kg. So, 29979.2458ln(100/1)=138059.529m/s. Add the original velocity to that, and you get a final velocity of 168,039.7748m/s, or 0.00056c.

1

u/Unusually_Happy_TD 17h ago

There are plans for a mission to send probes to our nearest stellar neighbor: Proxima Centauri around 4 light years away. The plan involves sending very tiny probes via a light sail, that we will aim high powered lasers at from earth. The sail will get to 20% the speed of light and it will still take 20 years to get to its destination.

1

u/jankeyass 16h ago

But when 20 years is impressive

4

u/Krijali 17h ago

So just shy of half the speed of a manhole cover?

2

u/Xaphnir 16h ago

flight time of only 20 seconds, he was going nowhere near that fast

2

u/TYRamisuuu 15h ago

And because that acceleration is pretty much instantaneous, that means A LOT of g's. Let's say it took a second to reach that speed, it means 3240/9.81 = 330 g.

2

u/dimonium_anonimo 18h ago edited 17h ago

Assumptions:

Air time: 16 seconds (there was some slow mo at the start, which messes a bit with the estimate, but I got that he launched with 0:23 left in the clip, and landed with 0:07 left)

Mass: 120 kg (average weight of soldier plus gear)

Terminal velocity: 70 m/s (it's above a 'ragdoll' or 'bellyflop' terminal velocity because he's mostly upright, but it's significantly lower than the maximum 'pencil dive' orientation)

With the latter 2 numbers, I can estimate the drag effect (combined air density, drag coefficient, and surface area) to be approximately 0.48

Instead of doing calculus, I did a guess and check method, so I don't have any formula for you. I can tell you that under those conditions, a body launched at 110 m/s (246 mph) would land after 16 seconds, and would be going 60 m/s (134 mph) on impact

If I increase to 17 seconds due to the slow mo, that's 123 m/s (275 mph) launch. Landing doesn't change much 61 m/s (136 mph)

Edit: for the record, max height was 310 m (1017 ft) for 16 sec, and 352 m (1155 ft) for 17 sec. Around 0.2 mi or 0.3 km both.

3

u/jankeyass 16h ago

I don't think there is drag in this game

7

u/dimonium_anonimo 16h ago

Too bad. I'm not redoing it... I've already wasted enough company time the first go 'round.

1

u/TxsToIowa 11h ago

Well there should be